Show that Newton's method applied to $x^{2}-c=0$ (where $c>0$ is some constant) produces the iterative scheme $x_{n+1}=\frac{1}{2}\left(x_{n}+c / x_{n}\right)$ for approximating $\sqrt{c}$. This scheme has been known for over 2000 years. To understand why it works, suppose that your initial guess $\left(x_{0}\right)$ for $\sqrt{c}$ is a little too small. How would $c / x_{0}$ compare to $\sqrt{c}$ ? Explain why the average of $x_{0}$ and $c / x_{0}$ would give a better approximation to $\sqrt{c}$.