00:01
Okay, so to find x1, so i'm going to use the formula.
00:07
X1 is equal to x0 minus f of x0 over f prime of x0.
00:19
So in this case, we're letting this function be f.
00:21
So with that, we need to plug negative 1 into here.
00:26
So with that, we get, so f of x0 is negative 1 cubed.
00:33
Plus 4 times negative 1 squared minus negative 1 minus 1.
00:42
So if we calculate that, you will get positive 3.
00:46
Then from here, we need to find the derivative of this function.
00:50
So the derivative of that function is 3x squared plus 8x minus 1.
00:59
So then we need to plug negative 1 in here to find f prime of x0.
01:03
So that'll give us 3 times negative 1 squared plus 8 times negative 1 minus 1.
01:14
And with that we get negative 6.
01:17
Now we need to plug 1, 2, 3 into this formula.
01:22
So we can calculate x1 now.
01:24
So x1 is equal to negative 1 minus f of x 0, which is 3.
01:31
And then over f prime of x here, which we just calculated to be negative 6.
01:35
So with that we will get negative 1 half.
01:40
Okay? so x1 is equal to negative 1 half.
01:46
So now i'm going to do the same thing in calculate x2.
01:50
Only x2, our formula, is going to be x1 minus f of x1 over f prime of x1...