Question
Determine the frequency of the following voltages and the phase angle between them.$$\begin{aligned}& v_1(t)=100 \sin \left(377 t+25^{\circ}\right) \mathrm{V} \\& v_2(t)=60 \cos \left(377 t-40^{\circ}\right) \mathrm{V}\end{aligned}$$
Step 1
The angular frequency \( \omega \) is the coefficient of \( t \) in the sine and cosine functions. From both equations, we have: \[ \omega = 377 \, \text{rad/s} \] Show more…
Show all steps
Your feedback will help us improve your experience
Supratim Pal and 80 other educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Determine the phase angles by which $v_{1}(t)$ leads $i_{1}(t)$ and $v_{1}(t)$ leads $i_{2}(t),$ where $$\begin{array}{l}v_{1}(t)=4 \sin \left(377 t+25^{\circ}\right) \mathrm{V} \\i_{1}(t)=0.05 \cos \left(377 t-20^{\circ}\right) \mathrm{A} \\i_{2}(t)=-0.1 \sin \left(377 t+45^{\circ}\right) \mathrm{A}\end{array}$$
Determine the relative phase relationship of the two waves $$\begin{array}{l}v_{1}(t)=10 \cos \left(377 t-30^{\circ}\right) \mathrm{V} \\v_{2}(t)=10 \cos \left(377 t+90^{\circ}\right) \mathrm{V}\end{array}$$
Determine the relative phase relationship of the two waves $$\begin{array}{l} v_{1}(t)=10 \cos \left(377 t-30^{\circ}\right) \mathrm{V} \\ v_{2}(t)=10 \cos \left(377 t+90^{\circ}\right) \mathrm{V} \end{array}$$
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD