0:00
Hi everyone.
00:01
So in order to tackle this question, okay, we'll see a first that is, so this would be first substitute is there or substrate is there.
00:31
H plus cn minus.
00:38
So this undergoescent to mechanism in presence of acetone as a solvent.
00:50
You'll get a product.
00:56
That is cs3 , then here is cyanide.
01:29
What is mechanism? mechanism of this reaction.
01:40
So in order to see the mechanism, we will first draw the substrate.
01:55
So in this case, you know, reaction is a sent to.
01:59
So nucleophile attacks from the side opposite to bromine.
02:05
So what you get is in other words a backside attack of a nucleophile takes place, backside attack of nucleophile takes place.
02:34
So it undergo ascent to reaction, backside attack, attack of cn minus to which bromine departs, but bromine is not attached to the chiral centre.
03:33
Bromene it is not attached to the chiral centre attached to the chiral centre.
03:52
So, so you can draw like this, stereochemistry is not taken into account, is not taken into account.
04:23
Then b, so you can draw like this, that is thick line indicates bromine is coming towards the observer or coming above the plate plus o minus ch3 this also undergo a second mechanism so in this case since the bromine is attached to the chiral carbon there is a inversion of configuration takes place so now we'll rate the mechanism.
05:38
No, what is mechanism basically? mechanism is step -by -step description of any chemical reaction.
05:53
So, you know, in this case, this is bromine.
06:00
Then this is hydrogen.
06:07
So, methoxodion, it attacks from the back side to which bromine departs.
06:32
So what we get is, so 100 % inversion of configuration takes place.
07:25
It takes place due to backset attack.
07:34
In first case also there is a b .r minus.
07:52
So, the s &2 mechanism, because bromine is at kyrr center, kyril carbon, 100 % inversion of configuration takes place takes place due to backside attack of o minus cs3 then we will move to the c part of the question that is here is here then ch2, ch2, ch2, cs3 plus cs3oh this procedure via sn1 mechanism.
09:36
So i'll get 2 product.
10:04
One is with a retention in configuration and one with inversion in configuration.
10:16
So this is 50 % you can say since it involved both retention and inversion, we can label it as a racemization.
10:38
A racemization takes place.
10:41
Now this mechanism, mechanism.
10:52
So you know we are then ch2, ch2, cs3.
11:16
So cbr becomes a bond becomes a polar in sn1 mechanism and therefore bromine first gets departed and she'll get a carbonium ion like this.
11:41
Now, you know, there are two possibility...