00:01
Question 51 is mostly an ideal gas law question, where knowing the liters, the temperature, and the pressure, we can calculate the moles of the gas.
00:16
For part a, we have 1 .25 liters at 250 kelvin and 1 .06 atmospheres.
00:24
So using the ideal gas law, pv equals nrt, we can rearrange it to solve for the moles, where moles is simply, pv divided by rt, r is the universal gas constant at 0 .08206 liter atmospheres per kelvin mole.
00:41
So to calculate the moles of the gas associated with 1 .06 atmospheres in 1 .25 liters and 250 kelvin, we simply plug these numerical values in for the variables and solve 4 moles and get 6 .26 times 10 the negative 2 moles.
01:00
For the next one, our gas is at .925 atmospheres in .8 liters, divide by r, multiplied by the temperature...