Determine the shear-stress variation over the cross section of the thin-walled tube as a function of elevation $y$ and show that $\tau_{\max }=2 V / A,$ where $A=2 \pi \pi .$ Hint: Choose a differential area element $d A=R t d \theta .$ Using $d Q=y d A$ formulate $Q$ for a circular section from $\theta$ to $(\pi-\theta)$ and show that $Q=2 R^{2} t \cos \theta,$ where $\cos \theta=\sqrt{R^{2}-y^{2}} / R$.