00:01
Hey, it's clarissa enumerate.
00:02
So we're going to let the domain be all integers.
00:05
For part a, the given statement means for all integers n, there exists an integer m that is larger than the square of the integer n.
00:14
This is true because n square plus 1, it's always going to be larger than the integer n square.
00:22
Part b, the statement means there exists an integer n, such that for all integers m, n is smaller than the integer n is smaller than the integer.
00:30
Square of the integer m.
00:32
This is true because let's say n equals negative 1 is always smaller than m square since m square is always going to be positive.
00:43
For part c this means for all integers n there exists an integer m such that their sum is zero.
00:53
This is true because the integer m equals n negative n so n plus n is equal to n plus negative n which is equal to 0...