00:03
So we have for all x to exist and y, such that x squared is equal to y.
00:10
Well, is the statement always true? yeah, it's true because, let's see.
00:18
We can just find, so let's say y is 2, then we can have an x that is, or if x is 1, then our y is 2, then our y is 4.
00:33
Is solving an equation based on where x is our y is that value squared for parts b we have that for all x there should exist some y such that x is equal to y squared okay well let's see if you think about this what about square roots of negative values well it isn't possible for a negative real number because the real square roots does not exist just the statement is false.
01:22
To part c, we have exist some x for all at y, such that x times y is equal to 0.
01:29
Ok, so this statement is true, because then what if, well, x can always equal 0.
01:35
0 times any number is always 0.
01:37
So part d, we have there is x and y, which that x plus y is not equal to y plus x.
01:52
Well, we know that the property of addition is commutative, so these two should be able to hold.
02:09
So this statement is all this meaningful.
02:13
Now we have e, which is for all x, there exists on x not equal to zero, such that this implies that there exists in y, such that x times y is equal to 1.
02:29
Well, yeah, so basically whatever value we have for x, we just take the inverse of x and let that equal to y, and then x times our inverse of x is equal to 1.
02:41
So this is true.
02:43
For f, we have there exists some x for all y, such that if y is not equal to fell, this implies that x comma y is equal to 1.
02:57
Okay, so this statement says that there exists a real number such that for every non -zero real number, their product equals 1, but this is obviously not true.
03:10
So the statement is felt...