00:01
Working a problem that uses kirchhoff's voltage law, which says that around any closed loop in a circuit that the sum of the voltage drops is equal to zero.
00:11
And so i'm going to take this circuit and break it down into the four smaller loops and work my way around clockwise and just add up the voltage drop.
00:22
So i'll start in the bottom left.
00:24
Since there i can find out what vx is and that tells me that minus 12 volts plus 4 volts.
00:32
Plus, sorry, v .x is equal to zero.
00:37
And so v .x is equal to eight volts.
00:41
I'm gonna use that in my subsequent loops.
00:46
So now in the top left, i have minus four volts, minus v sub one, and then that dependent voltage source is four times v .x, that's all equal to zero.
01:00
And therefore v .1 is equal to minus 36 volts.
01:08
Now on to the next one.
01:10
In the top right, i have plus 4 times v .x, and i have plus 6 volts, and i have plus v2, and that all equals to zero...