00:01
For this problem, we are given the vector field, f equals 2xyi plus x squared plus 2yzj plus y squared k, and we are asked first to determine if f is conservative.
00:13
Well, f will be conservative if it has continuous partial derivatives, which we can trivially see is true, and if its curl equals the zero vector.
00:22
So we need to check if that second part is true, if its curl equals the zero vector.
00:27
So we can calculate this using our determinant form over there.
00:33
So we'd have along the i column, dx, 2x, 2x, y.
00:38
Along the j column, we'd have dy, and then, not differentiating anything here yet.
00:47
So we'd have x squared plus 2yz.
00:51
And then along the k column, we'll have dz and y squared, which then means that our determinant, well, we would have first, d by d, y, squared, so 2y, minus d by dz, x squared plus 2yz, so 2y minus 2y, that clearly goes to zero...