00:01
The way i would approach this problem is actually rewrite the function.
00:05
So i'm not a big fan of this 1 over 1 minus x.
00:10
So i would actually rewrite it as 1 minus x to the negative first power.
00:15
So as i just do a few derivatives, i'm going to notice a pattern.
00:20
This is a chain rule where i can move that negative 1 in front, and then it's 1 minus x to the negative second power, but then you have to multiply by the derivative of the inside.
00:30
So just to clarify, this is equal to a negative times a negative is a positive, and then you have 1 minus x squared in the denominator.
00:39
So if i do the second derivative, again, the negatives cancel.
00:43
But now i need to do this chain rule where i bring the negative 2 in front.
00:48
1 minus x is now to the negative third power after i subtract 1 from the exponent times negative 1.
00:54
But again, the negatives are going to cancel.
00:57
But what doesn't cancel is you have a 2 on top.
01:00
And then 1 minus x to the positive third power...