Question

Differentiate the function. $g(x)=\frac{1}{\sqrt{x}}+\sqrt[4]{x}$

   Differentiate the function.
$g(x)=\frac{1}{\sqrt{x}}+\sqrt[4]{x}$
Single Variable Calculus: Early Transcendentals
Single Variable Calculus: Early Transcendentals
James Stewart,… 9th Edition
Chapter 3, Problem 17 ↓
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Differentiate the function. $g(x)=\frac{1}{\sqrt{x}}+\sqrt[4]{x}$
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Transcript

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00:01 This problem just involves being able to manipulate exponents.
00:06 So when you're looking at one over the square root of x and then plus the fourth root of x, i would just say, do you know that having something in the denominator makes it a negative exponent? so it's x to the negative.
00:21 The one -half power is the same thing as a square root.
00:25 Same thing with this one is the index is the denominator of your root.
00:30 And the numerator is that in case you're curious.
00:33 There's an implied two there.
00:35 Because now you can just use the power rule where you move the exponent in front and then you subtract one from the exponent...
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