Question

Differentiate the function. . $y=\frac{\sqrt{x}+x}{x^2}$ 

   Differentiate the function.
. $y=\frac{\sqrt{x}+x}{x^2}$
Single Variable Calculus: Early Transcendentals
Single Variable Calculus: Early Transcendentals
James Stewart,… 9th Edition
Chapter 3, Problem 24 ↓
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Differentiate the function. . $y=\frac{\sqrt{x}+x}{x^2}$
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Transcript

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00:01 It's clear so enumerate here.
00:02 So we have y is equal to square root of x plus x over x square.
00:09 This can be rewritten into x to the negative three halves plus x to the negative one power...
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