Question

Direct measurement of the normal boiling point of hydrogen peroxide is not possible because pure $\mathrm{H}_{2} \mathrm{O}_{2}$ explodes on heating. The boiling point can be estimated, however, from vapor-pressure data. Use the vapor pressures of 75.0 $\mathrm{mm}$ Hg at $89.0^{\circ} \mathrm{C}$ and 319.2 $\mathrm{mm}$ Hg at $125.0^{\circ} \mathrm{C}$ to estimate the boiling point. Compare your result with the value given in Section 18.11 .

   Direct measurement of the normal boiling point of hydrogen peroxide is not possible because pure $\mathrm{H}_{2} \mathrm{O}_{2}$ explodes on heating. The boiling point can be estimated, however, from vapor-pressure data. Use the vapor pressures of 75.0 $\mathrm{mm}$ Hg at $89.0^{\circ} \mathrm{C}$ and 319.2 $\mathrm{mm}$ Hg at $125.0^{\circ} \mathrm{C}$ to estimate the boiling point. Compare your result with the value given in Section 18.11 .
 
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 Chemistry
Chemistry
John E. Mcmurry,… 6th Edition
Chapter 18, Problem 128 ↓
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Direct measurement of the normal boiling point of hydrogen peroxide is not possible because pure $\mathrm{H}_{2} \mathrm{O}_{2}$ explodes on heating. The boiling point can be estimated, however, from vapor-pressure data. Use the vapor pressures of 75.0 $\mathrm{mm}$ Hg at $89.0^{\circ} \mathrm{C}$ and 319.2 $\mathrm{mm}$ Hg at $125.0^{\circ} \mathrm{C}$ to estimate the boiling point. Compare your result with the value given in Section 18.11 .
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Key Concepts

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Clausius-Clapeyron Equation
The Clausius-Clapeyron equation provides a quantitative relationship between vapor pressure and temperature. It is often used to estimate the enthalpy of vaporization and to extrapolate boiling points from vapor pressure data by assuming that the enthalpy of vaporization is relatively constant over the temperature range of interest.
Normal Boiling Point
The normal boiling point is defined as the temperature at which a liquid's vapor pressure equals standard atmospheric pressure (usually 1 atm). This concept is fundamental in physical chemistry as it characterizes a substance’s volatility and phase change behavior under normal conditions.
Vapor Pressure
Vapor pressure is the pressure exerted by a vapor in equilibrium with its liquid (or solid) phase at a given temperature. It is a key parameter in understanding phase transitions, and variations in vapor pressure with temperature help determine important thermodynamic properties such as the boiling point.
Extrapolation from Vapor-Pressure Data
Extrapolation in thermodynamics involves using known vapor pressure data at various temperatures to predict the properties of a system at temperatures beyond the measured range. For instance, by applying the Clausius-Clapeyron equation to available vapor pressure data, one can estimate the boiling point of a substance under conditions where direct measurement is impractical or dangerous.

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Hydrogen peroxide, $\mathrm{H}_{2} \mathrm{O}_{2}$, has a normal boiling point of $150^{\circ} \mathrm{C}$. Based on the data given in Figure 11.25 , would you expect hydrogen peroxide to have a higher or lower vapor pressure than water at $25^{\circ} \mathrm{C} ?$

Chemistry: The Central Science in SI Units, Global Edition


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Transcript

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00:01 In this problem, we are asked to consider hydrogen peroxide.
00:06 Hang on a second here because i lost my problem.
00:12 And we're told that hydrogen peroxide has a normal boiling point of 150 degrees celsius.
00:19 Based on the data given in a figure in your text, would we expect h202 to have a higher or lower vapor pressure than water? and i would expect it to have a lower vapor pressure.
00:54 Looking at the figure, well, first let's sketch these...
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