The numerator $x^{2}-3 x$ can be factored as $x(x-3)$. The denominator $x^{3}-27$ is a difference of cubes and can be factored as $(x-3)(x^{2}+3x+9)$. The expression $\frac{2 x}{2 x^{2}+6 x+18}$ can be simplified by factoring out a 2 from the denominator to get
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