The numerator of the first fraction, $x^{2}-6x+9$, can be factorized as $(x-3)^{2}$. The denominator of the first fraction, $x^{2}-x-6$, can be factorized as $(x-3)(x+2)$. The numerator of the second fraction, $x^{2}-9$, can be factorized as $(x-3)(x+3)$. The
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