Draw a crystal field energy-level diagram, and predict the number of unpaired electrons for each of the following:
$\begin{array}{ll}{\text { (a) }\left[\mathrm{Mn}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}} & {\text { (b) } \operatorname{Pt}\left(\mathrm{NH}_{3}\right)_{2} \mathrm{Cl}_{2}} \\ {\text { (c) }\left[\mathrm{FeO}_{4}\right]^{2-}} & {\text { (d) }\left[\mathrm{Ru}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+}(\text { low-spin) }}\end{array}$