For $\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$, the Fe ion is in the +2 oxidation state, so its electronic configuration is [Ar]3d$^6$.
For $\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{4-}$, the Fe ion is in the +2 oxidation state,
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