00:01
Hello, today we are doing problem 9 .60 and this problem asks us to draw a stepwise detailed mechanism for the following intramolecular reaction that forms a cyclic ether.
00:11
So obviously we have this reaction scheme that's given to us and we identify that in our starting material we have two alcohols which can be pronated from our strong acids.
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So as you guys know, i like redrawing my strong acids to h .a.
00:23
Just a simplified thing.
00:25
So now we have two options.
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We can either use the top alcohol to be protonated to protonated water or the bottom alcohol to be protonated to protonated water.
00:34
Well, now we've got to think about a little bit downstream of the reaction.
00:38
So typically when we have this sort of formation, we know that we want to form this product, this end product right here.
00:45
So we need to have and generate some sort of electrophile that our nucleophile can attack.
00:50
So the way that we can form an electrophile is that we will have water spontaneously falling off...