0:00
Hi everyone.
00:01
So in order to tackle this question, first one is two hexine.
00:08
Two hexine.
00:09
It's very simple.
00:10
That is first draw six carbon items, three, four, five and six.
00:15
Now, you know, then draw a single bond.
00:21
Then next one is two keyway numbering.
00:24
So this is the first carbon, second carbon, third.
00:27
You can say fourth, fifth and sixth.
00:29
So draw triple bond at second position.
00:34
Then number of hydrogens satisfy the valency of carbon using number of hydrogen.
00:40
So number of hydrogen is equal to 4 minus actual bond present.
00:44
So here 4 minus 1, 3.
00:48
Then here 4 minus 2.
00:53
2.
00:54
Make here 4 minus 2 2 and this is 4 minus 1 3.
00:58
So this is structure of xx.
01:00
Then second, 5 ethyl.
01:06
3 octane 5 ethyl 3 octane so draw 1 1 3 carbine 1 2 3 4 4 5 6 7 8 then draw a single bond the next give numbering 1 2 3 4 5 6 7 8 now three octane means you have to draw a triple bond between third and fourth carbon and phythyl so put ethyl sustenoned at fifth carbon then satisfy valency of carbon you know it is four minus one so it is three then this is four minus two two then four minus four zero zero so here four minus three one then here is four minus two two then four minus two and this is so this one, the structure.
02:10
The next structure, methyl acetylene.
02:15
Methylacetylene.
02:16
It's a common name.
02:18
So, you have tried here, methyl and then acetylene, cs3c, triple bond, c, h...