00:01
So in this question, we're asked to draw all of the enol pothomers for each of these ketones.
00:05
We're going to start from left to right because they start easy and get harder.
00:10
And we're going to ask the same set of questions repeatedly.
00:13
So when drawing an enol ptotomber, we need to ask, where can this double bond move to? and the answer to that is any adjacent carbon that has hydrogens on it.
00:23
If it does not have hydrogens on it, we cannot move the double bond to there.
00:27
So in this one, it can move either way.
00:30
Of course, it's a symmetrical ketone, so it doesn't matter.
00:34
Both substances would be the same.
00:35
There's only one e -an -o -totomer for this compound, and it would be this enol.
00:44
For this problem, we ask the exact same question, which ones have hydrogens? well, both carbons have hydrogens, and this time, it's not symmetrical.
00:53
With an asymmetrical one, we have two possible enols, so we're going to draw.
00:59
Both possible enols...