00:01
For this question, you're simply asked to draw as many resonant structures that obey the octet rule for the following molecules or ions.
00:08
First one is hn3.
00:10
Hydrogen has one valence electron and has five.
00:13
There are three of them, so we have a total of 16 valence electrons.
00:16
So let's put all three nitrogen in a row and then add the hydrogen on the end.
00:21
That's used up six, so we have ten left over.
00:27
So we could end up double bonding the nitrogen's.
00:30
That then uses up four more, so we have six left over.
00:34
One, two, three, four, five, six.
00:38
Now while the nitrogen have an octet, and the hydrogen has a duet, so we're good.
00:44
If we could have put a double bond here and a double bond here, there's no reason why we couldn't have put a trip bond between two of the nitrogen's, say on the left -hand side or the two nitrogen on the right hand side.
00:58
Next one is sulfur trioxide, dioxide.
01:00
Sulfur has six valence electrons.
01:02
Oxygen has six.
01:03
There are three of them.
01:04
So we have 24.
01:06
If we put sulfur in the middle, we put three oxygens around it, we've used up six of the 24.
01:11
So we have 18 left over.
01:13
Two, four, six, eight, ten, twelve, fourteen, sixteen, eighteen.
01:20
All the oxygens are good, but the sulfur only has six valence electrons...