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This question is in reference to resonant structures, and you're asked to draw as many resonant structures as possible for each of the following molecules or ions.
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The first one is so2.
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To draw the resonant structures, we must first draw the electron dot structure.
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And before we can draw the electron dot structure, we need to know the number of valence electrons.
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Sulfur has six, there's one of them.
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Oxygen has six.
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There are two of them.
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So we have a total of 18 valence electrons.
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So if we put sulfur in the middle and we put the three oxygens around it, we will end up, i'm sorry, the two oxygens around it, we will end up with four valence electrons having been used.
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That means we have 12 left over.
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So we've got one, two, three, four, five, six, seven, eight, nine, ten, eleven, twelve.
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We've got, sorry, fourteen, four, off of the 18 is 14.
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We just used up 12, so we got two more.
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So we'll put those two there on sulfur.
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The oxygens have an octet.
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The sulfur does not.
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So what we need to do is we need to take a lone pair off of one of the oxygens and have it become a bonding pair.
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If we can take it off the oxygen on the right, we could have taken it off the oxygen on the left, and we would get this as our second resonant structure.
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The second species is carbonate, co3 -2 -1.
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Carbon has four valence electrons, there's one of them.
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Oxygen has six, there are three of them, plus we have two more valence electrons from the two minus charge.
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That gives us a total of 24 valence electrons.
01:49
So if we put carbon in the middle and put all three oxygens around it, that will give us, well, we would have consumed six valence electrons, so we have 18 left over.
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So we could go 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12.
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13, 14, 15, 16, 17, 18.
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We used up all the valence electrons.
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All the oxygens have an octet, but the carbon does not.
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So we need to take a lone pair of electrons from one of the oxygens and make it a bonding pair...