Question
Draw orbital-energy splitting diagrams and use the spectrochemical series to show the orbital occupancy for each of the following (assuming that $\mathrm{H}_{2} \mathrm{O}$ is a weak-field ligand): $\begin{array}{ll}{\text { (a) }\left[\mathrm{Cr}(\mathrm{CN})_{6}\right]^{3-}} & {\text { (b) }\left[\mathrm{Rh}(\mathrm{CO})_{6}\right]^{3+}} & {\text { (c) }\left[\mathrm{Co}(\mathrm{OH})_{6}\right]^{4-}}\end{array}$
Step 1
For $\left[\mathrm{Cr}(\mathrm{CN})_{6}\right]^{3-}$, Cr is in the +3 oxidation state. Cr is a member of the 3d series and has 6 electrons in its ground state. Therefore, it has 3 d-electrons in the +3 oxidation state. For Show more…
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Draw orbital-energy splitting diagrams and use the spectrochemical series to show the orbital occupancy for each of the following (assuming that $\mathrm{H}_{2} \mathrm{O}$ is a weak-field ligand): $\begin{array}{llll}{\text { (a) }\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}} & {\text { (b) }\left[\mathrm{Cu}\left(\mathrm{H}_{2} \mathrm{O}\right)_{4}\right]^{2+}} & {\text { (c) [FeF }_{6} ]^{3-}}\end{array}$
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