00:03
Hello, so today we're just going to draw a couple compounds.
00:10
Let me zoom in a little bit.
00:13
So the first one that we have to draw is phenylbenzoate.
00:19
So first things first, let's just make a phenyl group.
00:25
So a phenyl group is just a benzene ring that's attached to an oxygen.
00:37
So, and then the second part is the benzate.
00:45
So benzeneic acid is just a carbonylic acid with a benzene as its alkyl -based chain.
00:54
So let's recreate that.
01:04
So there's our carbocytic acid formed into our ester.
01:09
And then let's just add this.
01:17
So, as you can see, here is the benzanoic acid, and then once we attach another benzene to the oxygen, it becomes phenylbenzoate.
01:38
Okay, onto n -ethyl, n -ethyl, methal, butanamide.
01:46
So n just means attached to the nitrogen.
01:48
So that means we have an ethyl group and a methyl group attached to a nitrogen.
01:55
So let's start with that.
01:58
So one.
02:02
So there's our methyl and there's our ethel attached to our nitrogen.
02:09
And we know the nitrogen is part of the carboxylic acid derivative.
02:12
So let's make that.
02:17
Oh, okay.
02:18
And what is attached? what is our base alkali chain? it's, as you can see, from the butan prefix right here, butan.
02:34
That means we have a four carbon base chain.
02:38
So one is already bound to the oxygen.
02:41
So that's one.
02:43
Here's our second, our third, and, oopsie.
02:50
Our fourth.
02:51
So it looks something like that.
03:01
So we have our four carbons on our base chain and then we have our methyl and our ethyl.
03:07
So let's move on to two four dimethyl pentanoil chloride.
03:12
So pentanoil chloride is the big key.
03:17
So first thing we want to do, let's make our pentanoil chloride, which just means we have this ocl and it's this base chain is a pentane.
03:36
So we have one carbon here.
03:39
Three, four, five.
03:42
So one, two, three, four, five.
03:45
And then we have a dimethyl, one on the two, and one on the four.
03:49
So this is the first.
03:52
We'll go to the second, and there's our methyl, third, and fourth.
03:58
So there we have it.
03:59
Two four dimethyl pentanoil chloride.
04:04
Okay.
04:04
Okay, on to the next one.
04:08
So we have methyl, one methyl cyclohexane hexylate.
04:16
So when we have this weird looking methyl out in the front, that means we're likely dealing with an ester or a thioester.
04:25
And we can see that for carboxylate.
04:28
So first thing we want to do is make our ester.
04:33
One, two.
04:40
All right, there is our methyl ester.
04:42
And what do we have attached to it? we have a one methyl cyclohexane carboxolate.
04:54
So this right here we know is the carboxolate.
05:02
So that means we have to go one back, add our methyl, and then add a cyclohexane.
05:18
Something like that.
05:21
So that's all this is.
05:23
It's, um, we have our methyl ester, and then we have our cyclohexane.
05:29
We have our one methyl, and then we have our carboxylate.
05:35
Okay, on to three, or ethyl -3 oxopentinoate.
05:41
So, once again, we're dealing with an ester...