00:03
In this question, we are drawing the condensed and skeletal structures for each of the compounds listed.
00:11
So starting with number one, one chloro three hexine.
00:14
So what i'm going to do is draw the condensed structures, and then we'll go back and do the skeletal structures.
00:19
So for number one, the condensed structure, we have three hexine.
00:25
So that's a six carbon alkan with the alkan on carbon three and one chloro.
00:30
So i'm going to go ahead and put that chloro out in front, which i'm going to go ahead and put that chloro.
00:33
Would make carbon 1 a ch2.
00:36
And then, so that's carbon 1, carbon 2, carbon 3 has our triple bond on it, which makes it have no hydrogens.
00:46
Carbon 4 also has no hydrogens, and then carbon 5 and carbon 6.
00:52
So there is our condensed structure for 1chloro3 hexine.
00:56
And then if we want to make this into a skeletal structure, we'll just draw lines instead of reading ch every time.
01:03
So we'll have chlorine on carbon one and then carbon two, carbon three, and then we have our triple bond on there, and that's four, five, six.
01:17
There's our skeletal structure.
01:21
B is cycloctine, so that is an eight -membered ring.
01:27
So one, two, three, four, five, six, seven, eight.
01:34
We have a triple bond.
01:36
In there somewhere.
01:38
And then these guys will have no hydrogens.
01:43
Let's connect everything.
01:46
And then everything else will be a ch2.
01:57
And then if you want to draw the skeletal structure, we'll do that same thing.
02:01
We'll draw an octagon and make one of them a triple bond.
02:10
So c is isopropylosacetylene.
02:12
So acetylene is, looks like this...