00:03
For this problem, we need to draw some orbital splitting diagrams.
00:08
And in this case, we're assuming they're all octahedra.
00:13
So that means they're all going to look like this.
00:19
But we need to figure out how many d electrons.
00:22
So if we start out with iron 2 plus, so iron starts out as 4s2d6, 3d6.
00:43
So that means we have d6.
00:51
In this case, if we want to look at high spin and low spin, so if we start with high spin, we'll fill all of the orbitals first, and then start pairing.
01:07
For low spin, we're going to fill the bottom orbitals first, and so it would look like that.
01:20
So this is high spin and the low spin.
01:28
Now if we go to iron 3, we'll just move back once.
01:39
We know it's a d5.
01:47
So if again we start with high spin, it looks like this.
01:57
If we do low spin, it looks like that.
02:16
Now next, we have nickel 2 plus...