00:01
So now we're going to work on problem 87 from chapter 5.
00:07
In this problem, we're asked to draw the lewis structure for h -c -s -n -h -2.
00:15
And then we're given some instructions about the order of what is bound to what.
00:25
And then we also want to label each bond as polar or non -polar.
00:34
So this molecule here will have a total of 18 electrons.
00:37
And so from the question we're told that carbon and nitrogen are bound together and the sulfur is bound to the carbon.
00:48
So based on the way the formula is written, we have an h bound to a carbon, bound to a nitrogen.
00:54
The sulfur will be bound to the carbon, and then we have two hydrogens bound to the nitrogen.
01:05
So this is five bonds here.
01:11
So we've assigned 10 electrons already.
01:15
We have eight left to assign.
01:17
Nitrogen, we know, will probably have a lone pair.
01:21
And so we need to complete the octet for nitrogen in that way.
01:24
So now we have six electrons left to assign...