00:03
This is the answer to chapter 11, problem number 37 from the smith organic chemistry textbook.
00:11
And this problem asks us to draw the products formed when 3 hexine is treated with each reagent.
00:19
And so rather than redraw 3 hexine four times, i drew it once at the top of the screen here.
00:26
And then i just drew our four reagent sets.
00:29
And i'm going to do my answers in green to distinguish them.
00:33
From the reagents.
00:36
Okay, so for a, we have two equivalents of hydrobromac acid.
00:45
And so that's going to add a hydrogen and a bromine for each equivalent.
00:54
And so it's going to add two hydrogens and two bromines.
00:58
And because this reaction follows markovnikov's role, both of the bromines are going to end up on the same carbon.
01:07
Okay, so then for b, we're going to have the addition of two equivalents of elemental bromine.
01:18
And so we will get addition of four bromines like this.
01:33
So first we'll get addition of one pair of bromines, and then the second pair of bromines will add as well...