00:01
Alright, so here we have our hex 1 -eem undergoing various reactions that we've been given.
00:08
So starting out at the top with our hcl with two equivalents, that's going to give us a product like this, where we've added chlorine onto each side of our molecule, just like that.
00:22
So you can probably assume that with another halogen, oh, whoops, i drew that one wrong, that's hbr.
00:30
We're going to get a very similar product.
00:32
You need to be correct in that thinking.
00:37
Just like that.
00:38
All right.
00:39
So how about if we have no hydrants? what if it's just pure chlorines? so we kind of brushed it over in the top ones, but you have to add hydrogens in there, and that's what the chlorines are going to replace here.
00:52
So what we see is we'll have chlorine, chlorine, chlorine, chlorine.
00:57
And the problems above, we got these hydrogens that attach to the end, otherwise it's the same problem.
01:03
Okay.
01:04
Now, what if we use this water, kind of sulfuric acid, solution? so what this is going to do is we're going to form kind of a keto -enal tautomization.
01:16
But we're going to form our alcohol on our inside ring.
01:20
And i'll show you what i mean by that...