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This is the answer to chapter 11, problem number 27 from the smith organic chemistry textbook.
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And this problem says, draw the seven isomeric alkynes, having molecular formula c6h10, and give the iupac name for each compound.
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Consider constitutional isomers only.
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Okay.
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And so in order to do this, we can start by drawing.
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A, well, so the best way is probably to draw a five carbon chain and then put the terminal al -kind on it.
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So that will look like that.
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And so this would just be one hexine.
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So we say where the triple bond is and we end in ein to show that it's an al -kind.
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So that's one hexine.
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So the next easiest one to do is going to be two hexine.
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Two hexine will look like this.
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One, two, three, four, five, six.
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So this would be two hexine.
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So again, we're saying it's a straight carbon chain with a triple bond at the two position.
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And so next we can do three hexine.
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And so three hexine is going to look like this.
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So this would be three hexine.
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And the next, so now we're sort of out of options for unbranched chains.
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So we can start making pentine chains instead.
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And so we can draw this molecule with a terminal triple bond here.
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This would be three methyl one pentine, three methyl one.
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One pentine.
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Okay...