00:03
This question asks us to draw seven alkynes with the formula c6h10 and then give both iupac and common names for each one.
00:13
So to do these types of problems, i like to start off with the structures that are just straight chains with the alkyne in different positions.
00:22
So we'll start with putting the alkyne at carbon one.
00:24
So that is one, two, three, four, five, six.
00:29
There is the first structure.
00:31
We could put it at position two so one two three four five six or we could put it at position three so one two three four five six and those are all the unique straight chain alkyines that we can make out of six carbons then we can take one of the uh carbons off there and make it a methyl group so we'll have a five carbon chain now so let's start with position one again.
01:03
One, two, three, four, five.
01:05
And we can put that methyl group there.
01:09
One, two, three, four, five.
01:11
We could also put it here.
01:13
So those are unique.
01:15
And then we could also do a methyl substituent with the alkyne in the second position.
01:19
So one, two, three, four, five.
01:23
And we can have a methyl right there.
01:25
And then the last thing we can do is take that methyl group over here and put it onto this carbon.
01:32
So we have a carbon with three methyl coming off of it.
01:35
So that would look like this.
01:37
One, two, three, four, five, six.
01:42
So there are all of our structures.
01:44
Now let's do iupac names.
01:47
So for the first one, we have six carbons.
01:49
So it's going to be hexine and the alkyne is on position one.
01:53
So one hexine.
01:55
Over here we have two hexine and three hexine.
02:03
And then in the second row, we have pentines because we took a methyl group as a substituent.
02:10
So this will be one pentine, but we also have a methyl group at one, two, three.
02:14
So three methyl, one pentine.
02:22
Here we put the methyl on carbon four, one, two, three, four.
02:25
So this will be four methyl, one pentine.
02:32
And then over here, we have the methyl group on one, two, three, four again...