Step 1:
The potential energy of a simple harmonic oscillator is given by $U(x) = \frac{1}{2} k' x^{2}$, which implies that the energy levels are given by $E_{n} = (n + \frac{1}{2}) \hbar \omega$, where $\omega = \sqrt{\frac{k'}{m}}$ is the angular frequency, $k'$
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