00:01
For this problem on the topic of electric forces and fields, we are told that an electron beam has a kinetic energy of 1 .6 times 10 to the minus 17 joules.
00:09
That's for each of the electrons in this beam.
00:12
We want to use this information to calculate the magnitude of the uniform electric field that will stop these electrons in 10 centimeters.
00:20
Then we want to know the time it will take for the electrons to come to rest, and we want to know what the electrons will do once they do come to rest.
00:29
Now, when an electron, which is a negative charge, moves a distance delta x in the direction of electric field, the work done on the electron w is equal to the electric force applied to the electron times delta x times cosine theta, where theta is the angle between the applied force and the displacement of electrons.
00:56
And this is equal to the charge on the electron, little e times the electric field strength e, which gives us the force times the distance delta x.
01:10
And this case, the electron is negatively charged, so the angle is 180 degrees.
01:19
So this gives us minus e times the electric field strength e times the distance delta x.
01:28
Now, from the work energy theorem, we have that minus e, e delta x, your kinetic energy theorem, rather, is equal to minus the initial kinetic energy of the electrons, which is k -e, which means that the electric field strength, e, is equal to the initial kinetic energy of the electrons divided by the charge of the electron times delta x.
02:04
And now we have an equation that relates the electric field with the distance.
02:08
And so we know the kinetic energy of each electron to initially be 1 .6 times 10 to the minus 17 joules divided by the charge of an electron 1 .6 times 10 to the minus 19 kuloms and the distance is 0 .1 meters, which is 10 centimeters.
02:39
And so the electric field strength that is required is 0 .1 meters.
02:44
1 times 10 to the power 3 newton's column...