00:03
So number 19 asks you to find theta if theta is the angle of the line segment that passes through the point negative 3 -4.
00:15
So negative 3 -4 is in quadrant 2, and i need to find a theta for that.
00:24
And theta needs to be in radiance between 0 and 4 -pi.
00:28
So we're going to use theta is 10 inverse of y over x.
00:35
You're going to set the calculator in radiance, and the calculator is going to always give you an angle between negative pi over 2 and pi over 2.
00:45
So it's going to give me an answer in quadrant 4 to start with.
00:49
When you plug that in, you get negative 0 .927, which isn't one of the answers we want, but it does get you started.
00:58
The ones in quadrant 2 are pi radians away from this one, so the theta's i'm allowed to use, we'll start at negative .97 plus pi.
01:13
So the first one we get is 2 .21 radiance.
01:18
That is in quadrant 2.
01:21
And since they gave me 0 to 4 pi, they want the first one here, and the second one all the way around and back to here.
01:29
So take 2 .21 and add 2 pi to it.
01:34
You get the second angle that works, which is 8 .50.
01:39
Letter b, wants you to look at the 0 .5 negative 1, which is in quadrant 4.
01:49
We're in degrees.
01:50
You have to set the calculator in degrees before you start finding the angle.
01:56
Theta is tan inverse of the y over the x, and you get theta is negative 11.
02:09
They want all the values from negative 360 around a positive 360.
02:16
Over 5 and down 1 gives me negative 310.
02:21
If i subtract 360, the next one would be too small.
02:26
So i'm going to write down my list of correct ones, negative 11 .310 degrees.
02:33
And then add 360 to that, and you get 348 .69...