00:01
In this problem, we are asked to, oops, i've got to get back to my problem here, answer a couple questions about the reaction i've written right here.
00:13
The rate of this reaction is found to be first order in the iodate, first order in sulfate, and first order for h plus.
00:49
A asks us to write the rate law, which is easy since they gave us everything.
01:00
So the rate law is this, for this, since it's first order, is the rate is equal to our constant times each concentration that we were just listed, not raised to, or just, i guess, raised to the first power.
01:26
Super simple for that one.
01:27
Next one isn't quite as simple, but that's okay.
01:32
B.
01:40
By what factor will the rate of the reaction change? if the ph is lowered from 5 .00 to 3 .50, does the rate? reaction proceed faster or slower i guess i should have written or slower at the lower ph and that's going to be our b so let's get ready for this one our change in ph will equal ph 2 minus ph 1 .50 now let's take a look at this following working through the equation here almost there okay so this is the equation we're going to use here.
06:02
So, oh, i've got something written there.
06:05
Let's go quickly by that.
06:08
So i get this following.
06:43
So this means that the rate will increase 32 -fold if the ph, let's just, will increase by 32 -fold.
07:13
So this means that the reaction is faster at the lower ph.
07:25
Okay, everything answered is answered for question b or part b.
07:31
Now let's do part c.
07:37
For part c, by using the concepts discussed in section 14 .6, i'm going to write c14 .6...