Question
Electrolysis of an alkaline earth metal chloride using a current of $5.00 \mathrm{~A}$ for $748 \mathrm{~s}$ deposits $0.471 \mathrm{~g}$ of metal at the cathode. What is the identity of the alkaline earth metal chloride?
Step 1
We know that current (I) = 5.00 A and time (t) = 748 s. Charge (Q) can be calculated using the formula Q = I × t. Q = 5.00 A × 748 s = 3740 C (coulombs) Show more…
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Electrolysis of an alkaline earth metal chloride using a current of $5.00 \mathrm{A}$ for 748 seconds deposits $0.471 \mathrm{g}$ of metal at the cathode. What is the identity of the alkaline earth metal chloride?
Electrolysis of an alkaline earth metal chloride using a current of 5.00 $\mathrm{A}$ for 748 seconds deposits 0.471 $\mathrm{g}$ of metal at an electrode. Is the metal deposited at the cathode or the anode of the electrolytic cell? What is produced at the other electrode? What is the identity of the alkaline earth metal?
Electrolysis of an alkaline earth metal chloride using a current of 5.00 A for 2020 s deposits 0.471 g of metal at the cathode. What is the identity of the alkaline earth metal chloride? a. CaCl2 b. MgCl2 c. RaCl2 d. BaCl2 e. BeCl2
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