00:01
In this problem, we're asked to describe how i might separate four different mixtures.
00:06
Our first mixture contains the zinc ion and the cadmium ion.
00:18
Cadmium 2 plus, the cadmium 2 ion, will precipitate out of solution at a ph of 1 when treated with h2s bubbling through the solution.
00:47
So you can separate that.
00:55
The zinc will not.
01:03
Our second, b, asks us to talk about c .r.
01:12
Oh, h, 3, and f .e.
01:18
Oh, h3.
01:20
Now, this one i had to do a little bit of looking up here, and what i decided to do is we can get both of these to precipitate out at the same conditions.
01:36
Once we have our precipitate, croh3 will form a complex ion, of course, is soluble, no precipitate anymore, and the complex ion is croh4 minus when treated with a strong base.
02:25
F -e -o -h -3 will not.
02:29
So it'll be a precipitate.
02:32
It will remain as a precipitate.
02:36
Going to go look up one thing super fast here...