Question
Equation of the circumcircle of the triangle whose vertices are $(0,0),(1,0),(-1,-3)$ is(a) $x^{2}+y^{2}-3 x+11 y=0$(b) $3\left(x^{2}+y^{2}-x\right)+11 y=0$(c) $3\left(x^{2}+y^{2}\right)+x-11 y=0$(d) $3\left(x^{2}+y^{2}\right)-x+11 y=0$
Step 1
We need to find the equation of the circumcircle of this triangle. The general equation of a circle is given by $x^{2}+y^{2}+2gx+2fy+c=0$. Show more…
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