Question
The equation $(x+y-6)(x y-3 x-y+3)=0$ represents the sides of a triangle then the equation of the circumcircle of the triangle is(A) $x^{2}+y^{2}-5 x-9 y+20=0$(B) $x^{2}+y^{2}-4 x-8 y+18=0$(C) $x^{2}+y^{2}-3 x-5 y+8=0$(D) $x^{2}+y^{2}+2 x-3 y-1=0$
Step 1
This gives us three equations which represent the sides of the triangle: $x=1$, $y=3$, and $x+y=6$. Show more…
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