Question
Error in the measurement of radius of sphere is $2 \%$. Then error in the calculation of volume will be(A) $1 \%$(B) $5 \%$(C) $3 \%$(D) $6 \%$
Step 1
This is represented as $\frac{\Delta r}{r} \times 100 = 2 \%$. Show more…
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Error in the measurement of radius of sphere is $2 \%$. The error in the measurement of volume is (a) $1 \%$ (b) 596 (c) $3 \%$ (d) 690
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Round 1
Error in the measurement of radius of sphere is 2%. Then error in the calculation of volume will be
If the error in measuring the radius of the sphere is $2 \%$ and that in measuring its mass is $3 \%$, then the error in measuring the density of material of the sphere is (a) $5 \%$ (b) $7 \%$ (c) $9 \%$ (d) $11 \%$
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