00:01
Here we are given the reaction, the balanced chemical equation for the reaction between ethanol and butanoic acid.
00:17
Whose formula is c3h7 c -o -o -h to produce ethylbutanoate whose formula is c3h7.
00:42
Coo, c2h5, and water.
00:50
And we have to determine, we have to calculate the mass of ethylbutanuate, the mass in grams, that can be produced out of 4 .50 moles of ethanol.
01:09
Because ethanol and ethyl butanuate are the substances involved in this question we are going to establish the mole ratio between these two substances we have one mole of ethanol reaction to produce one mole of ethyl butanuate i'm going to write now the this ratio one mole of ethyl of alcohol sorry ethanol reacts to produce one mole of ethylbutanoid.
01:53
Okay? we have to weigh, we are given moles and the answer has to be given in grams.
02:02
So we have to weigh up doing this.
02:04
Either we convert these moles now to grams and then we convert this mole ratio to mass ratio, or we calculate and then we compare this to mass ratio, we convert these moles to grams, and then we calculate the grams based on the mass ratio, or we calculate the moles of this and we only convert the obtained moles into grams, which is to be the quickest way, okay? so we calculate the most of ethylbutanoid first...