00:01
In part a, e is equal to workdown of engine 1 plus workdown of engine 2 divided by q1h which is equal to e1 q1h plus e2 2e2h divided by q1h.
00:32
Now, from here we know that q of 2h is equal to q of 1c, which is equal to q of 1h minus w in general, which is equal to q of 1h minus e1, q of 1h minus e1, q of 1h.
00:53
From here, we can find the value of e, which is e1, q1h plus e2, q1h minus e1h, q1h, q1h, this is divided by q1h, which is equal to e1 plus e2 minus e1e2.
01:13
Now, in part b, we have e is equal to e1 plus e2 minus e1e2, which is equal to 1 minus tti by th plus 1 minus tc by ti minus t i minus t i by t h multiply with 1 minus tc by t i from here we find the value 2 into t i by t h minus t c by t h minus 1 plus t i by t h plus t c by t h minus 1 plus t c by t h and minus tc by t n now we can write 1 minus tc by th h that is the value of now in part c we have the combination of reversible engine is itself a reversible engine so it has car not efficiency no improvement is net efficiency has resulted the combination of reversible engines is itself a reversible engine engine so it has the so it has the car not efficiency no improvement in net no improvement in net efficiency has resulted now in part d we have with wogden of engine 2 is equal to wogden of engine 1 where e is equal to wogden of engine 1 plus background of engine 2 divided by q1h...