00:01
We wish to evaluate this definite integral here.
00:03
So let's simplify this expression first.
00:06
We'll write this as the integral from 0 to 20, and then we'll copy the first part down, so e to the 0 .0 to t, and then we're going to distribute the 0 .12.
00:20
So then this becomes e to the power of 2 .4 minus 0 .12.
00:28
T.
00:32
Okay, and then next, so copy the integral down and then we can see that this can be split up into e to the 2 .4 times e with the power of negative 0 .12.
00:44
So let's go ahead and do that.
00:48
0 .0 to t times e to the 2 .4 times e the negative 0 .12t.
00:57
Okay, and then one last thing before we do our integration.
01:01
First we can complete pull the e of the 2 .4 out because that's just a constant.
01:05
So we'll pull it out in the front of our integral...