00:01
We wish to evaluate this definite integral here.
00:03
So let's simplify this expression here first.
00:09
So that's the integral from 0 to 30, 500 times e to the power of 0 .02t, and then we're going to distribute the 0 .09.
00:22
So that ends up being e to the power of 2 .7 minus 0 .092t.
00:34
So copy down the integral, copy down the 500, and then we can see that we can split this up into e to the 2 .7 times e to the negative 0 .019, which then we can combine with this eats the 0 .02 t.
00:53
So after doing all that, you should get e to the 2 .7 times e the negative 0 .0 .0 .7 times e the negative 0 .0.
01:08
So now we're going to factor the 500 times e to the 2 .7 out in front of our interval.
01:18
And that's because that is just a constant.
01:21
So we're only integrating e to the negative 0 .07t.
01:28
Okay, and we know how to do that...