00:02
Section 3 .2, problem 10, we're dealing with properties of determinants.
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Here we're presented with a 4 by 4 matrix.
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We're asked to use elementary row operations to get into upper triangular form.
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So that means all zeros below the diagonal.
00:16
So the determinant would be the product of all the numbers that are on the diagonal.
00:21
So let's just methodically start working through this.
00:24
I just go column by column.
00:26
So the first thing i want to do is let's clear this number you see right here.
00:32
So in order to do that, if i took negative three halves times row 1 plus row 2 and replace that into row 2, that would clear the number you see there.
00:46
So that would give me 2, 1, 3, 5.
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And then negative 3 halves times 2 is negative 3.
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Add to 3, you get 0.
00:58
0.
01:00
Negative 3 halves plus 1 is negative 3 halves add to 0.
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You get negative 3 halves.
01:09
Negative 3 halves and 3 is negative 9 halves.
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Negative 9 halves plus 1, that's negative 9 halves plus 2 halves is negative 7 halves.
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Negative 3 halves times 5 is negative 15 halves.
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So negative 15 halves plus 2, negative 15 halves plus 2, negative 15 halves plus 4 halves, is negative 11 halves.
01:30
And then the last three, last two rows remain unchanged.
01:41
Next thing i want to target is the item you see there.
01:45
So if i took negative two times row one plus row three and replaced row three, that would clear out the four that you see there.
01:57
So that leaves me with two, one, three, five, zero, minus three halves, minus seven halves, minus that.
02:09
11 halves.
02:11
And so negative 2 times 2 is negative 4 add to 400 0.
02:16
Negative 2 times 1 and negative 2.
02:18
Negative 2 plus 1 is negative 1.
02:22
And then negative 2 times 3 is negative 6.
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Negative 6 plus 4 is negative 2.
02:29
Negative 2 times 5 is negative 10.
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Negative 10 plus 3 is negative 7.
02:36
And then the last row remains unchanged.
02:42
The operation now is i only to clear that last element in the row.
02:47
So i could take negative five halves.
02:51
So negative five halves, let's just write that in red, negative five halves row one plus row four and place that into row four.
03:07
So that gives me two, one, three, five, zero minus three halves, minus seven 1�t minus 11 halves, 0 minus 1 minus 2, minus 7.
03:28
So negative 5 halves times 2 is negative 5, add the 5 ingot 0.
03:33
Negative 5 halves sums 1 is negative 5 halves...