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Section 3 .2, problem number 14, we're asked to find the determinant of a 5x5 matrix using elementary row operations to get it to upper triangular form and then find the determinant just by looking along the diagonal.
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So what i want to do here is just i like to go and just clear the first row.
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So everything under this 1 i need to turn into a 0.
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So the row operations will do that for me would be minus 5 times row 1.
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Plus row 2 and that will become the new row 2.
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So that will clear out this 5 for me.
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So let's do that operation.
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We're going to have 1, 2, 3, 4, 5.
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So negative 5 plus 5 is 0.
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Negative 5 times 2 is negative 10.
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Negative 10 plus 4 is negative 6.
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And then negative 5 times 3 is negative 15.
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15 plus 3 is negative 12 and then negative 5 times 4 is negative 20 negative 20 plus 2 negative 18 and then negative 5 times 5 is negative 25 negative 25 plus 1 negative 24 now to clear out this element here which is a 2 you could do negative 2 times row 1 plus row 3 and that will become our new row 3 so this gives me a 0 0 0 0 0 0 0.
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Negative 2 times 2 is negative 4, and negative 4 plus 3 is negative 1.
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Negative 2 times 3 is negative 6, negative 6 plus 4 is negative 2.
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Negative 2 times 4 is negative 8.
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Negative 8 plus 5 is negative 3.
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And then negative 2 times 5, negative 10, negative 10 plus 1 is, let's say negative 2...
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Negative 10, negative 10 plus 6 is negative 4.
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Now to clear out the 6, you're going to have negative 6 row 1 plus row 4...