00:01
Hello, here we have the integral of e to the u divided by 1 minus e to the u squared the u.
00:07
Okay, well, if we let this one minus e to the u, we could say be equal to u, maybe not u, maybe let that be equal, let's do maybe a k substitution.
00:18
Let's let's let's say, 1 minus e to the u.
00:24
Well, then if you differentiate both sides, we get that dk is going to be equal to, well, differentiating expect the u, we would get that the derivative of e to the u is a to u.
00:38
So then we have a negative sign here, so we'd have dk would be equal to just negative e to the u, and every fourth, we have negative dk is equal to e to the u, du...