evaluate the indefinite integral e^u / (1-e^u)² du
Added by Loola A.
Step 1
Let's set v = 1 - e^u. Then, -e^u du = dv. Now, we can rewrite the integral in terms of v: $$\int \frac{e^u}{(1-e^u)^2} du = -\int \frac{1}{v^2} dv$$ Now, we can integrate with respect to v: $$-\int \frac{1}{v^2} dv = \frac{1}{v} + C$$ Show more…
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