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Evaluate the integral.
$ \displaystyle \int \frac{x}{\sqrt{1 + x^2}}\ dx $
$\sqrt{1+x^{2}}+C$
Calculus 2 / BC
Chapter 7
Techniques of Integration
Section 3
Trigonometric Substitution
Integration Techniques
Missouri State University
Harvey Mudd College
Idaho State University
Boston College
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